20y^2=2-6y

Solution for 20y^2=2-6y equation:

20y^2=2-6y

We move all terms to the left:

20y^2-(2-6y)=0

We add all the numbers together, and all the variables

20y^2-(-6y+2)=0

We get rid of parentheses

20y^2+6y-2=0

a = 20; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·20·(-2)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-14}{2*20}=\frac{-20}{40}
=-1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+14}{2*20}=\frac{8}{40}
=1/5
$